How 1 + Cos (2A) = 2 Cos²A ?

How Cos (2A) = 2 Cos²A - 1 ?

As we know that
 ➡ Cos(2A) = Cos²A - Sin²A.......(1)

 or Sin²A = 1 - Cos²A......[put in (1) eq.]

➡Cos (2A) = Cos²A - (1 - Cos²A)
                = Cos²A - 1 + Cos²A
Hence, 
          Cos (2A) = 2 Cos²A - 1
         or 1 + Cos(2A) = 2 Cos²A

If angle is half i.e. θ = A
then, Cos (A) = 2 Cos²(A/2) - 1
      or 1 + Cos(A) = 2 Cos²(A/2)

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