How Sin²θ + Cos²θ = 1 ?

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According to Pythagoras theorem,

"the square of hypotenuse(H) is equal to the sum of square of base(B) and perpendicular(P)"

i.e.     H² = B² + P²
(Dividing both sides by H²)
we get,
    H²/H² = B²/H² + P²/H²
       1   = Sin²θ + Cos²θ    
                  ....(B/H  = sinθ and P/H = cosθ)
Hence, Sin²θ + Cos²θ = 1


May this video will be helpful for u.

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How   Sin²θ + Cos²θ = 1...?? According to Pythagoras theorem, "the square of hypotenuse(H) is equal to the sum of square of base(B) and perpendicular(P)" i.e.     H² = B² + P² (Dividing both sides by H²) we get,     H²/H² = B²/H² + P²/H²        1   = Sin²θ + Cos²θ                       ....(B/H  = sinθ and P/H = cosθ) Hence, Sin²θ + Cos²θ = 1 How Sin²θ + Cos²θ = 1?
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