How Sin(2A) = 2SinA CosA or Sin(A) = 2Sin(A/2) Cos(A/2) ?
Derivation of Sin(2A) = 2 SinA CosA or Sin(A) = 2Sin(A/2) Cos(A/2)? As we know that, ⇒Sin(A+B) = SinA CosB + CosA SinB 👉👉( Sin(A+B) = SinA CosB + CosA SinB ) put B= A then, ⇒Sin(A+A) = SinA CosA + CosA SinA ⇒Sin(2A) = SinA CosA + SinA CosA Hence, Sin(2A) = 2SinA CosA ⇒If angle will be halfed i.e. θ = A ⇒Hence, Sin(A) = 2Sin(A/2) Cos(A/2)
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