How Sin²θ + Cos²θ = 1?
How Sin²θ + Cos²θ = 1...?? According to Pythagoras theorem, "the square of hypotenuse(H) is equal to the sum of square of base(B) and perpendicular(P)" i.e. H² = B² + P² (Dividing both sides by H²) we get, H²/H² = B²/H² + P²/H² 1 = Sin²θ + Cos²θ ....(B/H = sinθ and P/H = cosθ) Hence, Sin²θ + Cos²θ = 1 How Sin²θ + Cos²θ = 1?
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