How Sin²θ + Cos²θ = 1?

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How
 Sin²θ + Cos²θ = 1...??

According to Pythagoras theorem,

"the square of hypotenuse(H) is equal to the sum of square of base(B) and perpendicular(P)"

i.e.     H² = B² + P²
(Dividing both sides by H²)
we get,
    H²/H² = B²/H² + P²/H²
       1   = Sin²θ + Cos²θ    
                  ....(B/H  = sinθ and P/H = cosθ)
Hence, Sin²θ + Cos²θ = 1
How Sin²θ + Cos²θ = 1?

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