How 1 + tan²θ = sec²θ?

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Derivation of tan²θ + 1 = sec²θ

As we know that,
              Sin²θ + Cos²θ = 1 

Divide by Cos²θ both sides ,
   we get,
Sin²θ/Cos²θ + Cos²θ/Cos²θ = 1/Cos²θ

Hence,   tan²θ + 1 = sec²θ


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