How tan(A+B) = (tanA + tanB)/(1- tanA tanB) ?
Derivation of tan(A+B) = (tanA + tanB)/(1- tanA tanB)
Trigonometric values w.r.t. Quadrants (1st, 2nd, 3rd and 4th)
👉Important Rules for trigonometric values in 1st ,2nd ,3rd and 4th Quadrant. {1}. Quadrant 1st: (90°-θ) and (360°+θ) All Trigonometric values are Positive (+). {2}. Quadrant 2nd : (90°+θ) and (180°-θ) Only values of sine (sin) and Cosecant (cosec) is positive (+) rest all Trigonometric values are negative (-). {3}. Quadrant 3rd: (180°+θ) and (270°-θ) Only values of tangent (tan) and Cotangent (cot) is positive (+) rest all Trigonometric values are negative (-). {4} . Quadrant 4th : (270°+θ) and (360° -θ) Only values of cosine (cos) and Secant (sec) is positive (+) rest all Trigonometric values are negative (-). 👇 The picture showing the values of all Trigonometric ratios in different quadrants :- # A Simple Way to remember A DD : All values positive S UGAR : Sine,Cosine are positive T O : Tan, cot are positive C OFEE : cos ,sec are positive
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