How Sin(A-B) = SinA CosB- CosA SinB
How Sin(A-B) = SinA CosB- CosA SinB
Cos (3A) = 4 Cos³A - 3 CosA
Cos (3A) = 4 Cos³A - 3 CosA?
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How Sin²Î¸ + Cos²Î¸ = 1?
How Sin²Î¸ + Cos²Î¸ = 1...?? According to Pythagoras theorem, "the square of hypotenuse(H) is equal to the sum of square of base(B) and perpendicular(P)" i.e. H² = B² + P² (Dividing both sides by H²) we get, H²/H² = B²/H² + P²/H² 1 = Sin²Î¸ + Cos²Î¸ ....(B/H = sinθ and P/H = cosθ) Hence, Sin²Î¸ + Cos²Î¸ = 1 How Sin²Î¸ + Cos²Î¸ = 1?
How Sin(A+B) = SinA CosB + CosA SinB ?
Derivation of Sin(A+B) = SinA CosB + CosA SinB
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